Nếu $\displaystyle\displaystyle\int\limits_0^3f(x)\mathrm{\,d}x=5$ và $\displaystyle\displaystyle\int\limits_0^1f(x)\mathrm{\,d}x=2$ thì $\displaystyle\displaystyle\int\limits_1^3f(x)\mathrm{\,d}x$ bằng
$-3$ | |
$3$ | |
$10$ | |
$7$ |
Chọn phương án B.
$\begin{array}{lclr}
&\displaystyle\int\limits_0^3f(x)\mathrm{\,d}x&=&\displaystyle\int\limits_0^1f(x)\mathrm{\,d}x+\displaystyle\int\limits_1^3f(x)\mathrm{\,d}x\\
\Leftrightarrow&5&=&2+\displaystyle\int\limits_1^3f(x)\mathrm{\,d}x\\
\Leftrightarrow&3&=&\displaystyle\int\limits_1^3f(x)\mathrm{\,d}x.
\end{array}$