Nếu $\displaystyle\displaystyle\int\limits_{2}^{5}f(x)dx=10$ thì $I=\displaystyle\displaystyle\int\limits_{5}^2\big[2-4f(x)\big]dx$ bằng
| $36$ | |
| $34$ | |
| $-38$ | |
| $-36$ |
Chọn phương án B.
$\begin{aligned}
I&=\displaystyle\int\limits_{5}^22\mathrm{d}x-4\displaystyle\int\limits_{5}^{2}f(x)\mathrm{d}x=2x\bigg|_5^2+4\displaystyle\int\limits_{2}^{5}f(x)\mathrm{d}x\\ &=-6+4\cdot10=34.
\end{aligned}$