Tích phân $\displaystyle\displaystyle\int\limits_{1}^{2}x^3\mathrm{\,d}x$ bằng
| $\dfrac{15}{3}$ | |
| $\dfrac{17}{4}$ | |
| $\dfrac{7}{4}$ | |
| $\dfrac{15}{4}$ |
Chọn phương án D.
Ta có $\displaystyle\int\limits_{1}^{2}x^3\mathrm{\,d}x=\dfrac{x^4}{4}\bigg|_1^2=\dfrac{2^4}{4}-\dfrac{1^4}{4}=\dfrac{15}{4}$.