Cho \(\displaystyle\int\limits_a^b f(x)\mathrm{\,d}x=-3\) và \(\displaystyle\int\limits_a^b g(x)\mathrm{\,d}x=4\). Tính \(I=\displaystyle\int\limits_a^b [4f(x)-3g(x)]\mathrm{\,d}x\).
\(I=25\) | |
\(I=-24\) | |
\(I=24\) | |
\(I=0\) |
Chọn phương án B.
\(\begin{aligned}
I&=\displaystyle\int\limits_a^b[4f(x)-3g(x)]\mathrm{\,d}x\\
&=4\displaystyle\int\limits_a^b f(x)\mathrm{\,d}x-3\displaystyle\int\limits_a^b g(x)\mathrm{\,d}x\\
&=4\cdot{(-3)}-3\cdot {4}=-24.
\end{aligned}\)