Tính $f'\left(\dfrac{\pi}{2}\right)$ biết $f\left(x\right)=\dfrac{\cos x}{1+\sin x}$.
| $-2$ | |
| $\dfrac{1}{2}$ | |
| $0$ | |
| $-\dfrac{1}{2}$ |
Chọn phương án D.
Ta có $f'\left(x\right)=-\dfrac{1}{1+\sin x}$.
Suy ra $f'\left(\dfrac{\pi}{2}\right)=-\dfrac{1}{1+\sin \dfrac{\pi}{2}}=-\dfrac{1}{2}$.