Tính tích phân \(I=\displaystyle\int\limits_{0}^{1}(x+1)^2\mathrm{\,d}x\).
\(I=\dfrac{1}{2}\) | |
\(I=\dfrac{1}{3}\) | |
\(I=\dfrac{7}{3}\) | |
\(I=-\dfrac{1}{2}\) |
Chọn phương án C.
\(I=\displaystyle\int\limits_{0}^{1}(x+1)^2\mathrm{\,d}x=\dfrac{(x+1)^3}{3}\bigg|_0^1=\dfrac{8}{3}-\dfrac{1}{3}=\dfrac{7}{3}\).