Giải phương trình \(\sin\left(\dfrac{2x}{3}-60^\circ\right)=0\).
| \(x=k180^\circ\,(k\in\mathbb{Z})\) | |
| \(x=90^\circ+k\dfrac{3\pi}{2}\,(k\in\mathbb{Z})\) | |
| \(x=60^\circ+k180^\circ\,(k\in\mathbb{Z})\) | |
| \(x=90^\circ+k270^\circ\,(k\in\mathbb{Z})\) |
Chọn phương án D.
\(\begin{aligned}
\sin\left(\dfrac{2x}{3}-60^\circ\right)=0\Leftrightarrow&\dfrac{2x}{3}-60^\circ=k180^\circ\\
\Leftrightarrow&\dfrac{2x}{3}=60^\circ+k180^\circ\\
\Leftrightarrow&2x=180^\circ+k540^\circ\\
\Leftrightarrow&x=90^\circ+k270^\circ\,(k\in\mathbb{Z}).
\end{aligned}\)