Tính \(\lim\limits_{x\to2}\dfrac{\sqrt[3]{3x^2-4}-\sqrt{3x-2}}{x+1}\).
| \(-\dfrac{3}{2}\) | |
| \(-\dfrac{2}{3}\) | |
| \(0\) | |
| \(+\infty\) |
Chọn phương án C.
\(\lim\limits_{x\to2}\dfrac{\sqrt[3]{3x^2-4}-\sqrt{3x-2}}{x+1}=\dfrac{\sqrt[3]{3\cdot2^2-4}-\sqrt{3\cdot2-2}}{2+1}=0\).